(7x+1)/5=-x^2

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Solution for (7x+1)/5=-x^2 equation:


x in (-oo:+oo)

(7*x+1)/5 = (-x)^2 // - (-x)^2

(7*x+1)/5-(-x)^2 = 0

(7*x+1)/5-x^2 = 0

(7*x+1)/5+(5*(-x^2))/5 = 0

5*(-x^2)+7*x+1 = 0

7*x-5*x^2+1 = 0

7*x-5*x^2+1 = 0

7*x-5*x^2+1 = 0

DELTA = 7^2-(-5*1*4)

DELTA = 69

DELTA > 0

x = (69^(1/2)-7)/(-5*2) or x = (-69^(1/2)-7)/(-5*2)

x = (69^(1/2)-7)/(-10) or x = (69^(1/2)+7)/10

(x-((69^(1/2)-7)/(-10)))*(x-((69^(1/2)+7)/10)) = 0

((x-((69^(1/2)-7)/(-10)))*(x-((69^(1/2)+7)/10)))/5 = 0

((x-((69^(1/2)-7)/(-10)))*(x-((69^(1/2)+7)/10)))/5 = 0 // * 5

(x-((69^(1/2)-7)/(-10)))*(x-((69^(1/2)+7)/10)) = 0

( x-((69^(1/2)+7)/10) )

x-((69^(1/2)+7)/10) = 0 // + (69^(1/2)+7)/10

x = (69^(1/2)+7)/10

( x-((69^(1/2)-7)/(-10)) )

x-((69^(1/2)-7)/(-10)) = 0 // + (69^(1/2)-7)/(-10)

x = (69^(1/2)-7)/(-10)

x in { (69^(1/2)+7)/10, (69^(1/2)-7)/(-10) }

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